Egyptian Journal of Forensic Sciences (Dec 2017)

Method development for determination of residual Chlorpyrifos in the grapes by Tlc-fid

  • Vimukti Chauhan,
  • Surbhi Tomar,
  • Yanika Saini,
  • R. M. Tripathi

DOI
https://doi.org/10.1186/s41935-017-0032-8
Journal volume & issue
Vol. 7, no. 1
pp. 1 – 7

Abstract

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Abstract Background Fruits and vegetables are daily staple food of human community. It is important to include fruits and vegetables in our daily diet to remain healthy and active. Even though fruits and vegetables are healthy, but they are equally prone to pests and diseases which attack them during their time of production as well as storage, thus, degrading their yield and quality. So, to prevent these issues farmers use high amount of pesticides and other products, this enters in our body orally. A large amount of pesticides gets removed from the human body in the form of urine and fecal matter but, still some pesticides (especially chlorpyrifos) are very persistent and can remain in human body for a long term. This study aims at the presentation of a method for the determination of chlorpyrifos from grapes sample by TLC-FID technique. The residue of pesticides was extracted from the sample in ethyl acetate. The grapes sample was macerated, extracted, filtered and analyzed by the proposed method. The analyzed sample showed chlorpyrifos contamination even in the lowest amount taken for analysis. Results The TLC-FID technique using mobile phase consist of hexane: acetone (9:1, v/v)has been found to be more effective and less tedious as chromarods were used for performing chromatographic separation. Chlorpyrifos were extracted from the samples by liquid-liquid extraction before the analysis. The method developed can be used to detect chlorpyrifos residues in a concentration as minimum as 0.02 mg/Kg. Conclusion The regression data was used to calculate the limit of detection and the recovery range was of 97.9% -99.8%. The correlation coefficient calculated from the calibration curve was quite good (R2 = 0.9996).

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