(E)-2-(4-Nitrobenzylideneamino)benzamide

Abstract

The title compound, C14H11N3O3, adopts an E conformation, with a dihedral angle of 41.8 (1) ° between the mean planes of the two benzene rings. One of the amino H atoms forms an intramolecular hydrogen bond with the amide N atom, while the other H atom forms an intermolecular hydrogen bond with the carbonyl O atom of an adjacent molecule, forming dimers about inversion centers. A non-classical intermolecular C—H...O hydrogen bond also links adjacent molecules into dimers.